So, we are solving for V1: how much of the concentrated solution we will need. There is a concentrated 12 Molar HCl solution (M1) and we want to end up with 50 milliliters (V2) of a 3 Molar HCl solution (M2). To use this equation, we need to figure out what the problem is giving us. How many milliliters of the 12 M HCl will you need to prepare the 3 M solution? Well, let’s go back to our dilution equation: M1V1 = M2V2. You want to dilute this concentrated HCl with water so that you have 50 mL of a 3 M hydrochloric acid solution. Let’s do an example! Say you have a 12 M (M = moles/L) solution of hydrochloric acid. ![]() You can solve for the concentration or volume of the concentrated or dilute solution using the equation: M1V1 = M2V2, where M1 is the concentration in molarity (moles/Liters) of the concentrated solution, V2 is the volume of the concentrated solution, M2 is the concentration in molarity of the dilute solution (after more solvent has been added), and V2 is the volume of the dilute solution. If you are adding more solvent, the volume of the whole solution is going to increase as the concentration of the solution decreases. ![]() Calculations are very important in Chemistry.įirst we need to understand what a dilution is:Ī dilution is when you have a solution of a certain concentration and you add more solvent (remember: the substance that does the dissolving!) to decrease the concentration.
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